$\text{Question: Find the equation of the line passing through the point } (11,2) \text{ and slope }m=11\text{. Then determine its }y\text{-intercept}$.$\text{Answer: }$$\text{The equation of the line passing through the point }(x_0,y_0) \text{ and slope }m \text{ is given by }y-y_0=m(x-x_0)\text{.}$$\text{In this problem }x_0=11\text{ and }y_0=2\text{ and }m=11\text{.}$$\text{So the equation of the given line is }$$y-(2) = 11(x-(11))$$\text{or, }y-2=11(x-11)$$\text{or, }y-2=11x-121$$\text{or, }y=11x-121+2$$\text{or, }y=11x-119$$\text{The }y\text{-intercept of the line is }-119$