Integral using Substitution (Polynomials and Rationals)

\int (9 x^{2} - 3 x + 1) d x

=

\int 9 x^{2} d x + \int -3 x d x + \int 1 d x

=

9 \int x^{2} d x - 3 \int x d x + \int 1 d x

=

9 (\frac{1}{3} x^{3}) - 3 (\frac{1}{2} x^{2}) + (x) + C

=

3 x^{3} - \frac{3}{2} x^{2} + x + C

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Copyright © Dayal D. Purohit, Ph.D.(Mathematics)