Integral of Polynomials
∫
(
-5
x
5
-
9
x
4
-
6
x
2
+
5
x
-
1
)
d
x
=
∫
-5
x
5
d
x
+
∫
-9
x
4
d
x
+
∫
-6
x
2
d
x
+
∫
5
x
d
x
+
∫
-1
d
x
=
-
5
∫
x
5
d
x
-
9
∫
x
4
d
x
-
6
∫
x
2
d
x
+
5
∫
x
d
x
-
∫
1
d
x
=
-
5
(
1
6
x
6
)
-
9
(
1
5
x
5
)
-
6
(
1
3
x
3
)
+
5
(
1
2
x
2
)
-
(
x
)
+
C
=
-5
6
x
6
-
9
5
x
5
-
2
x
3
+
5
2
x
2
-
x
+
C
Algebra
Analytic Geometry
Differential Calculus
Integral Calculus
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Copyright © Dayal D. Purohit, Ph.D.(Mathematics)