Derivatives of Exponentials I

\frac{d}{d x} e^{-7 x^{3} - 9 x^{2} + 9 x}

=

\frac{d}{d x} e^{u}

=

\frac{d}{d u} (e^{u}) \frac{d u}{d x}

=

e^{u} (-21 x^{2} - 18 x + 9)

=

e^{-7 x^{3} - 9 x^{2} + 9 x} (-21 x^{2} - 18 x + 9)

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Copyright © Dayal D. Purohit, Ph.D.(Mathematics)