Integrals of Simple Exponential Functions

I = \int e^{x + \frac{11}{6}} d x

Put

u = x + \frac{11}{6}, then

d u = (1) d x

Or,

d u = d x

So,

I = \int e^{u} d u

Or,

I = \int e^{u} d u

Or,

I = e^{u} + C

Or,

I = e^{x + \frac{11}{6}} + C

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